Base | Representation |
---|---|
bin | 10111001110000101100010… |
… | …10101110110111100000011 |
3 | 20200210102202222012110012012 |
4 | 23213002301111312330003 |
5 | 23143043021401342011 |
6 | 300333203423123135 |
7 | 13520034503042441 |
oct | 1347026125667403 |
9 | 220712688173165 |
10 | 51061546512131 |
11 | 152a709791a541 |
12 | 58880a07434ab |
13 | 226511097491c |
14 | c8756ba73b91 |
15 | 5d83647aea8b |
hex | 2e70b1576f03 |
51061546512131 has 4 divisors (see below), whose sum is σ = 51356699960352. Its totient is φ = 50766393063912.
The previous prime is 51061546512121. The next prime is 51061546512143. The reversal of 51061546512131 is 13121564516015.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51061546512131 is a prime.
It is a super-2 number, since 2×510615465121312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51061546512121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147576723851 + ... + 147576724196.
It is an arithmetic number, because the mean of its divisors is an integer number (12839174990088).
Almost surely, 251061546512131 is an apocalyptic number.
51061546512131 is a deficient number, since it is larger than the sum of its proper divisors (295153448221).
51061546512131 is a wasteful number, since it uses less digits than its factorization.
51061546512131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 295153448220.
The product of its (nonzero) digits is 108000, while the sum is 41.
The spelling of 51061546512131 in words is "fifty-one trillion, sixty-one billion, five hundred forty-six million, five hundred twelve thousand, one hundred thirty-one".
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