Base | Representation |
---|---|
bin | 10111001110001100110011… |
… | …00100110011010001101011 |
3 | 20200210210211111122111201010 |
4 | 23213012121210303101223 |
5 | 23143124011320242103 |
6 | 300335050204555003 |
7 | 13520233163336334 |
oct | 1347063144632153 |
9 | 220723744574633 |
10 | 51065442743403 |
11 | 152a8807178790 |
12 | 58889a9552a63 |
13 | 22655b1c3330a |
14 | c8781b2d528b |
15 | 5d84e1888903 |
hex | 2e719993346b |
51065442743403 has 8 divisors (see below), whose sum is σ = 74277007626816. Its totient is φ = 30948753177800.
The previous prime is 51065442743347. The next prime is 51065442743417. The reversal of 51065442743403 is 30434724456015.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51065442743403 - 245 = 15881070654571 is a prime.
It is a super-2 number, since 2×510654427434032 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51065442743423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 773718829413 + ... + 773718829478.
It is an arithmetic number, because the mean of its divisors is an integer number (9284625953352).
Almost surely, 251065442743403 is an apocalyptic number.
51065442743403 is a deficient number, since it is larger than the sum of its proper divisors (23211564883413).
51065442743403 is a wasteful number, since it uses less digits than its factorization.
51065442743403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1547437658905.
The product of its (nonzero) digits is 4838400, while the sum is 48.
The spelling of 51065442743403 in words is "fifty-one trillion, sixty-five billion, four hundred forty-two million, seven hundred forty-three thousand, four hundred three".
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