Base | Representation |
---|---|
bin | 10111001110110011010001… |
… | …11011011001000010000001 |
3 | 20200212210011020120220210111 |
4 | 23213121220323121002001 |
5 | 23143443313430334423 |
6 | 300352344144031321 |
7 | 13521564134226556 |
oct | 1347315073310201 |
9 | 220783136526714 |
10 | 51086101418113 |
11 | 15306548490873 |
12 | 58909b4002541 |
13 | 2267524c0b4a8 |
14 | c8881ac78a2d |
15 | 5d8d0036260d |
hex | 2e7668ed9081 |
51086101418113 has 4 divisors (see below), whose sum is σ = 52734040173568. Its totient is φ = 49438162662660.
The previous prime is 51086101418111. The next prime is 51086101418161. The reversal of 51086101418113 is 31181410168015.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51086101418113 - 21 = 51086101418111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51086101418111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 823969377681 + ... + 823969377742.
It is an arithmetic number, because the mean of its divisors is an integer number (13183510043392).
Almost surely, 251086101418113 is an apocalyptic number.
It is an amenable number.
51086101418113 is a deficient number, since it is larger than the sum of its proper divisors (1647938755455).
51086101418113 is a wasteful number, since it uses less digits than its factorization.
51086101418113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1647938755454.
The product of its (nonzero) digits is 23040, while the sum is 40.
The spelling of 51086101418113 in words is "fifty-one trillion, eighty-six billion, one hundred one million, four hundred eighteen thousand, one hundred thirteen".
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