Base | Representation |
---|---|
bin | 10111001110110011010100… |
… | …00010010110110110011001 |
3 | 20200212210012112121001201011 |
4 | 23213121222002112312121 |
5 | 23143443333211141101 |
6 | 300352350050453521 |
7 | 13521564451320553 |
oct | 1347315202266631 |
9 | 220783175531634 |
10 | 51086120021401 |
11 | 15306557a37793 |
12 | 58909ba2942a1 |
13 | 2267528a22c5a |
14 | c8881d51c4d3 |
15 | 5d8d01cd9751 |
hex | 2e766a096d99 |
51086120021401 has 4 divisors (see below), whose sum is σ = 51289650380304. Its totient is φ = 50882589662500.
The previous prime is 51086120021393. The next prime is 51086120021441. The reversal of 51086120021401 is 10412002168015.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51086120021401 - 23 = 51086120021393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51086120021441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101765179075 + ... + 101765179576.
It is an arithmetic number, because the mean of its divisors is an integer number (12822412595076).
Almost surely, 251086120021401 is an apocalyptic number.
It is an amenable number.
51086120021401 is a deficient number, since it is larger than the sum of its proper divisors (203530358903).
51086120021401 is a wasteful number, since it uses less digits than its factorization.
51086120021401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203530358902.
The product of its (nonzero) digits is 3840, while the sum is 31.
Adding to 51086120021401 its reverse (10412002168015), we get a palindrome (61498122189416).
The spelling of 51086120021401 in words is "fifty-one trillion, eighty-six billion, one hundred twenty million, twenty-one thousand, four hundred one".
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