51100115441345 has 4 divisors (see below), whose sum is σ = 61320138529620. Its totient is φ = 40880092353072.

The previous prime is 51100115441321. The next prime is 51100115441369. The reversal of 51100115441345 is 54314451100115.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (51100115441321) and next prime (51100115441369).

It can be written as a sum of positive squares in 2 ways, for example, as 31817135486224 + 19282979955121 = 5640668^2 + 4391239^2 .

It is a cyclic number.

It is not a de Polignac number, because 51100115441345 - 2¹⁰ = 51100115440321 is a prime.

It is a super-2 number, since 2×51100115441345² (a number of 28 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5110011544130 + ... + 5110011544139.

It is an arithmetic number, because the mean of its divisors is an integer number (15330034632405).

Almost surely, 2^{51100115441345} is an apocalyptic number.

It is an amenable number.

51100115441345 is a deficient number, since it is larger than the sum of its proper divisors (10220023088275).

51100115441345 is a wasteful number, since it uses less digits than its factorization.

51100115441345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10220023088274.

The product of its (nonzero) digits is 24000, while the sum is 35.

The spelling of 51100115441345 in words is "fifty-one trillion, one hundred billion, one hundred fifteen million, four hundred forty-one thousand, three hundred forty-five".