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5110055110561 = 7171972607191
BaseRepresentation
bin100101001011100011100…
…0001010000011110100001
3200002111221112020000021011
41022113013001100132201
51132210343102014221
614511305451300521
71035121633523602
oct112270701203641
920074845200234
105110055110561
1116a0186988a95
126a644314a741
132b0b50b1876b
14139483dd3da9
158cdce5a31e1
hex4a5c70507a1

5110055110561 has 4 divisors (see below), whose sum is σ = 5182027717824. Its totient is φ = 5038082503300.

The previous prime is 5110055110507. The next prime is 5110055110577. The reversal of 5110055110561 is 1650115500115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5110055110561 - 215 = 5110055077793 is a prime.

It is a super-2 number, since 2×51100551105612 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5110055110661) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35986303525 + ... + 35986303666.

It is an arithmetic number, because the mean of its divisors is an integer number (1295506929456).

Almost surely, 25110055110561 is an apocalyptic number.

It is an amenable number.

5110055110561 is a deficient number, since it is larger than the sum of its proper divisors (71972607263).

5110055110561 is an equidigital number, since it uses as much as digits as its factorization.

5110055110561 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71972607262.

The product of its (nonzero) digits is 3750, while the sum is 31.

The spelling of 5110055110561 in words is "five trillion, one hundred ten billion, fifty-five million, one hundred ten thousand, five hundred sixty-one".

Divisors: 1 71 71972607191 5110055110561