Base | Representation |
---|---|
bin | 101111100101110101… |
… | …001000101110110011 |
3 | 11212220021201000022022 |
4 | 233211311020232303 |
5 | 1314123220131430 |
6 | 35250354102055 |
7 | 3456214345334 |
oct | 574565105663 |
9 | 155807630268 |
10 | 51100552115 |
11 | 1a742a25158 |
12 | 9aa157a92b |
13 | 4a84a84ab2 |
14 | 268a97428b |
15 | 14e12d94e5 |
hex | be5d48bb3 |
51100552115 has 4 divisors (see below), whose sum is σ = 61320662544. Its totient is φ = 40880441688.
The previous prime is 51100552103. The next prime is 51100552121. The reversal of 51100552115 is 51125500115.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51125500115 = 5 ⋅10225100023.
It is a cyclic number.
It is not a de Polignac number, because 51100552115 - 234 = 33920682931 is a prime.
It is a super-2 number, since 2×511005521152 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5110055207 + ... + 5110055216.
It is an arithmetic number, because the mean of its divisors is an integer number (15330165636).
Almost surely, 251100552115 is an apocalyptic number.
51100552115 is a deficient number, since it is larger than the sum of its proper divisors (10220110429).
51100552115 is a wasteful number, since it uses less digits than its factorization.
51100552115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10220110428.
The product of its (nonzero) digits is 1250, while the sum is 26.
The spelling of 51100552115 in words is "fifty-one billion, one hundred million, five hundred fifty-two thousand, one hundred fifteen".
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