Base | Representation |
---|---|
bin | 10111001111010001101100… |
… | …11111100100101010101001 |
3 | 20200221100022120100122220020 |
4 | 23213220312133210222221 |
5 | 23144230241343242441 |
6 | 300404045024151053 |
7 | 13523012660433060 |
oct | 1347506637445251 |
9 | 220840276318806 |
10 | 51102435134121 |
11 | 1531246a439418 |
12 | 5893bb2168489 |
13 | 2268c28b689c7 |
14 | c8952a2791d7 |
15 | 5d94592c6e66 |
hex | 2e7a367e4aa9 |
51102435134121 has 16 divisors (see below), whose sum is σ = 77870714404224. Its totient is φ = 29201265108864.
The previous prime is 51102435134117. The next prime is 51102435134131. The reversal of 51102435134121 is 12143153420115.
It is not a de Polignac number, because 51102435134121 - 22 = 51102435134117 is a prime.
It is a super-2 number, since 2×511024351341212 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51102435134131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 185356 + ... + 10111341.
It is an arithmetic number, because the mean of its divisors is an integer number (4866919650264).
Almost surely, 251102435134121 is an apocalyptic number.
It is an amenable number.
51102435134121 is a deficient number, since it is larger than the sum of its proper divisors (26768279270103).
51102435134121 is a wasteful number, since it uses less digits than its factorization.
51102435134121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10533040.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 51102435134121 its reverse (12143153420115), we get a palindrome (63245588554236).
The spelling of 51102435134121 in words is "fifty-one trillion, one hundred two billion, four hundred thirty-five million, one hundred thirty-four thousand, one hundred twenty-one".
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