Base | Representation |
---|---|
bin | 10111001111010001111001… |
… | …10000011001000111100011 |
3 | 20200221100120220001220012011 |
4 | 23213220330300121013203 |
5 | 23144231000243102223 |
6 | 300404103300213351 |
7 | 13523015404512526 |
oct | 1347507460310743 |
9 | 220840526056164 |
10 | 51102540206563 |
11 | 1531251378494a |
12 | 589402139a257 |
13 | 2268c44867251 |
14 | c8953a1cabbd |
15 | 5d946362e80d |
hex | 2e7a3cc191e3 |
51102540206563 has 16 divisors (see below), whose sum is σ = 52921711687680. Its totient is φ = 49287194826016.
The previous prime is 51102540206521. The next prime is 51102540206587. The reversal of 51102540206563 is 36560204520115.
It is a cyclic number.
It is not a de Polignac number, because 51102540206563 - 217 = 51102540075491 is a prime.
It is a super-2 number, since 2×511025402065632 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51102540206363) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 114861606 + ... + 115305652.
It is an arithmetic number, because the mean of its divisors is an integer number (3307606980480).
Almost surely, 251102540206563 is an apocalyptic number.
51102540206563 is a deficient number, since it is larger than the sum of its proper divisors (1819171481117).
51102540206563 is a wasteful number, since it uses less digits than its factorization.
51102540206563 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 448346.
The product of its (nonzero) digits is 216000, while the sum is 40.
Adding to 51102540206563 its reverse (36560204520115), we get a palindrome (87662744726678).
The spelling of 51102540206563 in words is "fifty-one trillion, one hundred two billion, five hundred forty million, two hundred six thousand, five hundred sixty-three".
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