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51102540206563 = 2913672903444047
BaseRepresentation
bin10111001111010001111001…
…10000011001000111100011
320200221100120220001220012011
423213220330300121013203
523144231000243102223
6300404103300213351
713523015404512526
oct1347507460310743
9220840526056164
1051102540206563
111531251378494a
12589402139a257
132268c44867251
14c8953a1cabbd
155d946362e80d
hex2e7a3cc191e3

51102540206563 has 16 divisors (see below), whose sum is σ = 52921711687680. Its totient is φ = 49287194826016.

The previous prime is 51102540206521. The next prime is 51102540206587. The reversal of 51102540206563 is 36560204520115.

It is a cyclic number.

It is not a de Polignac number, because 51102540206563 - 217 = 51102540075491 is a prime.

It is a super-2 number, since 2×511025402065632 (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (51102540206363) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 114861606 + ... + 115305652.

It is an arithmetic number, because the mean of its divisors is an integer number (3307606980480).

Almost surely, 251102540206563 is an apocalyptic number.

51102540206563 is a deficient number, since it is larger than the sum of its proper divisors (1819171481117).

51102540206563 is a wasteful number, since it uses less digits than its factorization.

51102540206563 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448346.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 51102540206563 its reverse (36560204520115), we get a palindrome (87662744726678).

The spelling of 51102540206563 in words is "fifty-one trillion, one hundred two billion, five hundred forty million, two hundred six thousand, five hundred sixty-three".

Divisors: 1 29 1367 2903 39643 84187 444047 3968401 12877363 115083629 607012249 1289068441 17603355221 37382984789 1762156558847 51102540206563