Base | Representation |
---|---|
bin | 101111100101111110… |
… | …111100111101101011 |
3 | 11212220110112202010111 |
4 | 233211332330331223 |
5 | 1314124400002410 |
6 | 35250525155151 |
7 | 3456245253442 |
oct | 574576747553 |
9 | 155813482114 |
10 | 51103125355 |
11 | 1a7444224a7 |
12 | 9aa23bbab7 |
13 | 4a85476119 |
14 | 268b043d59 |
15 | 14e1646b8a |
hex | be5fbcf6b |
51103125355 has 4 divisors (see below), whose sum is σ = 61323750432. Its totient is φ = 40882500280.
The previous prime is 51103125347. The next prime is 51103125361. The reversal of 51103125355 is 55352130115.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55352130115 = 5 ⋅11070426023.
It is not a de Polignac number, because 51103125355 - 23 = 51103125347 is a prime.
It is a super-2 number, since 2×511031253552 (a number of 22 digits) contains 22 as substring.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5110312531 + ... + 5110312540.
It is an arithmetic number, because the mean of its divisors is an integer number (15330937608).
Almost surely, 251103125355 is an apocalyptic number.
51103125355 is a deficient number, since it is larger than the sum of its proper divisors (10220625077).
51103125355 is a wasteful number, since it uses less digits than its factorization.
51103125355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10220625076.
The product of its (nonzero) digits is 11250, while the sum is 31.
The spelling of 51103125355 in words is "fifty-one billion, one hundred three million, one hundred twenty-five thousand, three hundred fifty-five".
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