Base | Representation |
---|---|
bin | 100101001100000000100… |
… | …1110111010001010011001 |
3 | 200002121110120222022222222 |
4 | 1022120001032322022121 |
5 | 1132214343113031310 |
6 | 14511550420353425 |
7 | 1035155063133533 |
oct | 112300116721231 |
9 | 20077416868888 |
10 | 5111031767705 |
11 | 16a0638208a56 |
12 | 6a6676245875 |
13 | 2b0c78271ab6 |
14 | 1395379c6853 |
15 | 8ce3a1c3055 |
hex | 4a6013ba299 |
5111031767705 has 4 divisors (see below), whose sum is σ = 6133238121252. Its totient is φ = 4088825414160.
The previous prime is 5111031767693. The next prime is 5111031767741. The reversal of 5111031767705 is 5077671301115.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1332288445504 + 3778743322201 = 1154248^2 + 1943899^2 .
It is not a de Polignac number, because 5111031767705 - 24 = 5111031767689 is a prime.
It is a super-2 number, since 2×51110317677052 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511103176766 + ... + 511103176775.
It is an arithmetic number, because the mean of its divisors is an integer number (1533309530313).
Almost surely, 25111031767705 is an apocalyptic number.
It is an amenable number.
5111031767705 is a deficient number, since it is larger than the sum of its proper divisors (1022206353547).
5111031767705 is a wasteful number, since it uses less digits than its factorization.
5111031767705 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1022206353546.
The product of its (nonzero) digits is 154350, while the sum is 44.
The spelling of 5111031767705 in words is "five trillion, one hundred eleven billion, thirty-one million, seven hundred sixty-seven thousand, seven hundred five".
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