Base | Representation |
---|---|
bin | 101111100110100000… |
… | …111000110110111001 |
3 | 11212221002021201020212 |
4 | 233212200320312321 |
5 | 1314134134141213 |
6 | 35251444000505 |
7 | 3456414004514 |
oct | 574640706671 |
9 | 155832251225 |
10 | 51112021433 |
11 | 1a749449230 |
12 | 9aa5390135 |
13 | 4a8726c385 |
14 | 268c2bbd7b |
15 | 14e23029a8 |
hex | be6838db9 |
51112021433 has 8 divisors (see below), whose sum is σ = 55765931520. Its totient is φ = 46459338480.
The previous prime is 51112021393. The next prime is 51112021459. The reversal of 51112021433 is 33412021115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51112021433 - 228 = 50843585977 is a prime.
It is a super-2 number, since 2×511120214332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 51112021399 and 51112021408.
It is not an unprimeable number, because it can be changed into a prime (51112020433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218585 + ... + 387302.
It is an arithmetic number, because the mean of its divisors is an integer number (6970741440).
Almost surely, 251112021433 is an apocalyptic number.
It is an amenable number.
51112021433 is a deficient number, since it is larger than the sum of its proper divisors (4653910087).
51112021433 is a wasteful number, since it uses less digits than its factorization.
51112021433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 613567.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 51112021433 its reverse (33412021115), we get a palindrome (84524042548).
The spelling of 51112021433 in words is "fifty-one billion, one hundred twelve million, twenty-one thousand, four hundred thirty-three".
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