Base | Representation |
---|---|
bin | 10111001111100100111001… |
… | …01000010100101101010011 |
3 | 20200222022220122012221000000 |
4 | 23213302130220110231103 |
5 | 23144412342042414200 |
6 | 300412511252101043 |
7 | 13523526211662000 |
oct | 1347623450245523 |
9 | 220868818187000 |
10 | 51112738638675 |
11 | 1531687750093a |
12 | 5895ba8904783 |
13 | 2269bab6b016c |
14 | c89c268448a7 |
15 | 5d985db37300 |
hex | 2e7c9ca14b53 |
51112738638675 has 672 divisors, whose sum is σ = 113258779545600. Its totient is φ = 22855724640000.
The previous prime is 51112738638671. The next prime is 51112738638677. The reversal of 51112738638675 is 57683683721115.
51112738638675 is a `hidden beast` number, since 5 + 1 + 112 + 73 + 8 + 6 + 386 + 75 = 666.
It is not a de Polignac number, because 51112738638675 - 22 = 51112738638671 is a prime.
It is a super-2 number, since 2×511127386386752 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is not an unprimeable number, because it can be changed into a prime (51112738638671) by changing a digit.
It is a polite number, since it can be written in 671 ways as a sum of consecutive naturals, for example, 118591040710 + ... + 118591041140.
Almost surely, 251112738638675 is an apocalyptic number.
51112738638675 is an abundant number, since it is smaller than the sum of its proper divisors (62146040906925).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51112738638675 is an equidigital number, since it uses as much as digits as its factorization.
51112738638675 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 852 (or 818 counting only the distinct ones).
The product of its digits is 50803200, while the sum is 63.
The spelling of 51112738638675 in words is "fifty-one trillion, one hundred twelve billion, seven hundred thirty-eight million, six hundred thirty-eight thousand, six hundred seventy-five".
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