Base | Representation |
---|---|
bin | 1001100001010100… |
… | …01011100100101011 |
3 | 111012012212112010211 |
4 | 10300222023210223 |
5 | 40432000043430 |
6 | 2203105321551 |
7 | 240443411662 |
oct | 46052134453 |
9 | 14165775124 |
10 | 5111331115 |
11 | 21932387a0 |
12 | ba79362b7 |
13 | 635c3baa7 |
14 | 366ba1dd9 |
15 | 1edae872a |
hex | 130a8b92b |
5111331115 has 16 divisors (see below), whose sum is σ = 6696730080. Its totient is φ = 3714257920.
The previous prime is 5111331107. The next prime is 5111331161.
5111331115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5111331115 - 23 = 5111331107 is a prime.
It is a super-2 number, since 2×51113311152 = 52251411534334286450, which contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29787 + ... + 105403.
It is an arithmetic number, because the mean of its divisors is an integer number (418545630).
Almost surely, 25111331115 is an apocalyptic number.
5111331115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5111331115 is a deficient number, since it is larger than the sum of its proper divisors (1585398965).
5111331115 is a wasteful number, since it uses less digits than its factorization.
5111331115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76862.
The product of its digits is 225, while the sum is 22.
The square root of 5111331115 is about 71493.5739419985. The cubic root of 5111331115 is about 1722.5744657144.
It can be divided in two parts, 51113 and 31115, that added together give a palindrome (82228).
The spelling of 5111331115 in words is "five billion, one hundred eleven million, three hundred thirty-one thousand, one hundred fifteen".
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