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5111401305451 = 731211009923167
BaseRepresentation
bin100101001100001011101…
…0000100101010101101011
3200002122102100022210111011
41022120113100211111223
51132221122213233301
614512051221044351
71035200201143210
oct112302720452553
920078370283434
105111401305451
1116a0807868151
126a6759b566b7
132b10069a8b9c
14139570adbb07
158ce5c86aa51
hex4a61742556b

5111401305451 has 16 divisors (see below), whose sum is σ = 5844304076800. Its totient is φ = 4379174616960.

The previous prime is 5111401305427. The next prime is 5111401305467. The reversal of 5111401305451 is 1545031041115.

It is a cyclic number.

It is not a de Polignac number, because 5111401305451 - 25 = 5111401305419 is a prime.

It is a super-2 number, since 2×51114013054512 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5111401309451) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 220621270 + ... + 220644436.

It is an arithmetic number, because the mean of its divisors is an integer number (365269004800).

Almost surely, 25111401305451 is an apocalyptic number.

5111401305451 is a deficient number, since it is larger than the sum of its proper divisors (732902771349).

5111401305451 is a wasteful number, since it uses less digits than its factorization.

5111401305451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36394.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 5111401305451 its reverse (1545031041115), we get a palindrome (6656432346566).

The spelling of 5111401305451 in words is "five trillion, one hundred eleven billion, four hundred one million, three hundred five thousand, four hundred fifty-one".

Divisors: 1 7 3121 10099 21847 23167 70693 162169 31518979 72304207 220632853 233963533 506129449 1637744731 730200186493 5111401305451