511141241 has 4 divisors (see below), whose sum is σ = 550459812. Its totient is φ = 471822672.

The previous prime is 511141181. The next prime is 511141271. The reversal of 511141241 is 142141115.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 142141115 = 5 ⋅28428223.

It can be written as a sum of positive squares in 2 ways, for example, as 249640000 + 261501241 = 15800^2 + 16171^2 .

It is a cyclic number.

It is not a de Polignac number, because 511141241 - 2⁶ = 511141177 is a prime.

It is a super-2 number, since 2×511141241² = 522530736502040162, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (511141271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19659266 + ... + 19659291.

It is an arithmetic number, because the mean of its divisors is an integer number (137614953).

Almost surely, 2^511141241 is an apocalyptic number.

It is an amenable number.

511141241 is a deficient number, since it is larger than the sum of its proper divisors (39318571).

511141241 is a wasteful number, since it uses less digits than its factorization.

511141241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39318570.

The product of its digits is 160, while the sum is 20.

The square root of 511141241 is about 22608.4329620609. The cubic root of 511141241 is about 799.5524793908.

Adding to 511141241 its reverse (142141115), we get a palindrome (653282356).

The spelling of 511141241 in words is "five hundred eleven million, one hundred forty-one thousand, two hundred forty-one".