Base | Representation |
---|---|
bin | 100101001100100000010… |
… | …0100011001000110100011 |
3 | 200002201012122102211011210 |
4 | 1022121000210121012203 |
5 | 1132224032124122232 |
6 | 14512244055441203 |
7 | 1035223315064235 |
oct | 112310044310643 |
9 | 20081178384153 |
10 | 5112094364067 |
11 | 16a1032aa6369 |
12 | 6a6912086203 |
13 | 2b10b7457942 |
14 | 1395d8b8a255 |
15 | 8ce9d61b5cc |
hex | 4a6409191a3 |
5112094364067 has 12 divisors (see below), whose sum is σ = 6843390142280. Its totient is φ = 3394484844000.
The previous prime is 5112094364059. The next prime is 5112094364089. The reversal of 5112094364067 is 7604634902115.
5112094364067 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5112094364067 - 23 = 5112094364059 is a prime.
It is a super-2 number, since 2×51120943640672 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5112094365067) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13334842 + ... + 13712847.
Almost surely, 25112094364067 is an apocalyptic number.
5112094364067 is a deficient number, since it is larger than the sum of its proper divisors (1731295778213).
5112094364067 is an equidigital number, since it uses as much as digits as its factorization.
5112094364067 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27048194 (or 27047943 counting only the distinct ones).
The product of its (nonzero) digits is 1088640, while the sum is 48.
The spelling of 5112094364067 in words is "five trillion, one hundred twelve billion, ninety-four million, three hundred sixty-four thousand, sixty-seven".
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