Base | Representation |
---|---|
bin | 100101001100100001101… |
… | …1111100000010100011011 |
3 | 200002201100001201211210112 |
4 | 1022121003133200110123 |
5 | 1132224132203231210 |
6 | 14512253011034535 |
7 | 1035224452025462 |
oct | 112310337402433 |
9 | 20081301654715 |
10 | 5112143414555 |
11 | 16a1058758761 |
12 | 6a692659ba4b |
13 | 2b10c466cab8 |
14 | 1396014b79d9 |
15 | 8cea2aa9d05 |
hex | 4a6437e051b |
5112143414555 has 8 divisors (see below), whose sum is σ = 6136431642000. Its totient is φ = 4088475035296.
The previous prime is 5112143414491. The next prime is 5112143414597. The reversal of 5112143414555 is 5554143412115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5112143414555 - 26 = 5112143414491 is a prime.
It is a super-2 number, since 2×51121434145552 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 154943900 + ... + 154976889.
It is an arithmetic number, because the mean of its divisors is an integer number (767053955250).
Almost surely, 25112143414555 is an apocalyptic number.
5112143414555 is a deficient number, since it is larger than the sum of its proper divisors (1024288227445).
5112143414555 is a wasteful number, since it uses less digits than its factorization.
5112143414555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 309924093.
The product of its digits is 240000, while the sum is 41.
The spelling of 5112143414555 in words is "five trillion, one hundred twelve billion, one hundred forty-three million, four hundred fourteen thousand, five hundred fifty-five".
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