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5112234003 = 37417229753
BaseRepresentation
bin1001100001011011…
…01000000000010011
3111012021120101200010
410300231220000103
540432212442003
62203140530003
7240454162212
oct46055500023
914167511603
105112234003
1121937a5088
12ba80b0903
13636196a46
14366d59079
151edc26003
hex130b68013

5112234003 has 8 divisors (see below), whose sum is σ = 6817260688. Its totient is φ = 3407681664.

The previous prime is 5112233983. The next prime is 5112234011. The reversal of 5112234003 is 3004322115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-5112234003 is a prime.

It is a super-2 number, since 2×51122340032 = 52269873002858808018, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5112254003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92626 + ... + 137127.

It is an arithmetic number, because the mean of its divisors is an integer number (852157586).

Almost surely, 25112234003 is an apocalyptic number.

5112234003 is a deficient number, since it is larger than the sum of its proper divisors (1705026685).

5112234003 is a wasteful number, since it uses less digits than its factorization.

5112234003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237173.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 5112234003 is about 71499.8881327796. Note that the first 3 decimals coincide. The cubic root of 5112234003 is about 1722.6758874517.

Adding to 5112234003 its reverse (3004322115), we get a palindrome (8116556118).

The spelling of 5112234003 in words is "five billion, one hundred twelve million, two hundred thirty-four thousand, three".

Divisors: 1 3 7417 22251 229753 689259 1704078001 5112234003