Base | Representation |
---|---|
bin | 100101001100100111000… |
… | …0010000000101010110011 |
3 | 200002201210101110002220001 |
4 | 1022121032002000222303 |
5 | 1132230012434411430 |
6 | 14512322324530431 |
7 | 1035232026660535 |
oct | 112311602005263 |
9 | 20081711402801 |
10 | 5112320232115 |
11 | 16a1139547378 |
12 | 6a6975850a17 |
13 | 2b112219b285 |
14 | 13961ab83855 |
15 | 8ceb33853ca |
hex | 4a64e080ab3 |
5112320232115 has 8 divisors (see below), whose sum is σ = 6134813150400. Its totient is φ = 4089836937792.
The previous prime is 5112320232067. The next prime is 5112320232143.
5112320232115 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5112320232115 - 27 = 5112320231987 is a prime.
It is a super-2 number, since 2×51123202321152 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1180594 + ... + 3408583.
It is an arithmetic number, because the mean of its divisors is an integer number (766851643800).
Almost surely, 25112320232115 is an apocalyptic number.
5112320232115 is a deficient number, since it is larger than the sum of its proper divisors (1022492918285).
5112320232115 is a wasteful number, since it uses less digits than its factorization.
5112320232115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4811981.
The product of its (nonzero) digits is 3600, while the sum is 28.
It can be divided in two parts, 5112320 and 232115, that added together give a palindrome (5344435).
The spelling of 5112320232115 in words is "five trillion, one hundred twelve billion, three hundred twenty million, two hundred thirty-two thousand, one hundred fifteen".
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