Base | Representation |
---|---|
bin | 10111001111111000101010… |
… | …11011110010111000010011 |
3 | 20201000100022112101211111011 |
4 | 23213330111123302320103 |
5 | 23200101112431111430 |
6 | 300421424544431351 |
7 | 13524353255251003 |
oct | 1347742533627023 |
9 | 221010275354434 |
10 | 51123355332115 |
11 | 15320325335850 |
12 | 5898070318557 |
13 | 226abb108c5a1 |
14 | c8a552858003 |
15 | 5d9c80c0e22a |
hex | 2e7f156f2e13 |
51123355332115 has 16 divisors (see below), whose sum is σ = 66926266984800. Its totient is φ = 37179984683520.
The previous prime is 51123355332097. The next prime is 51123355332151.
51123355332115 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-51123355332115 is a prime.
It is a super-2 number, since 2×511233553321152 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4717734 + ... + 11158123.
It is an arithmetic number, because the mean of its divisors is an integer number (4182891686550).
Almost surely, 251123355332115 is an apocalyptic number.
51123355332115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
51123355332115 is a deficient number, since it is larger than the sum of its proper divisors (15802911652685).
51123355332115 is a wasteful number, since it uses less digits than its factorization.
51123355332115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15934422.
The product of its digits is 202500, while the sum is 40.
The spelling of 51123355332115 in words is "fifty-one trillion, one hundred twenty-three billion, three hundred fifty-five million, three hundred thirty-two thousand, one hundred fifteen".
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