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5112453504361 = 7730350500623
BaseRepresentation
bin100101001100101010111…
…1110011001110101101001
3200002202010200020001001011
41022121111332121311221
51132230301044114421
614512343445223521
71035235235530420
oct112312576316551
920082120201034
105112453504361
1116a11a77a3825
126a69b2401ba1
132b11439912a8
141396307562b7
158cebee0d4e1
hex4a655f99d69

5112453504361 has 4 divisors (see below), whose sum is σ = 5842804004992. Its totient is φ = 4382103003732.

The previous prime is 5112453504337. The next prime is 5112453504413. The reversal of 5112453504361 is 1634053542115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5112453504361 - 27 = 5112453504233 is a prime.

It is a super-2 number, since 2×51124535043612 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5112453505361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365175250305 + ... + 365175250318.

It is an arithmetic number, because the mean of its divisors is an integer number (1460701001248).

Almost surely, 25112453504361 is an apocalyptic number.

It is an amenable number.

5112453504361 is a deficient number, since it is larger than the sum of its proper divisors (730350500631).

5112453504361 is an equidigital number, since it uses as much as digits as its factorization.

5112453504361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 730350500630.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 5112453504361 in words is "five trillion, one hundred twelve billion, four hundred fifty-three million, five hundred four thousand, three hundred sixty-one".

Divisors: 1 7 730350500623 5112453504361