Base | Representation |
---|---|
bin | 100101001100101100101… |
… | …1101101001001011100011 |
3 | 200002202021202100012200220 |
4 | 1022121121131221023203 |
5 | 1132230411034302230 |
6 | 14512353335414123 |
7 | 1035236546124432 |
oct | 112313135511343 |
9 | 20082252305626 |
10 | 5112512025315 |
11 | 16a1227834452 |
12 | 6a6a09b24343 |
13 | 2b1152b40c86 |
14 | 13963842b119 |
15 | 8cec511cd10 |
hex | 4a6597692e3 |
5112512025315 has 16 divisors (see below), whose sum is σ = 8181376164000. Its totient is φ = 2726220772352.
The previous prime is 5112512025307. The next prime is 5112512025391. The reversal of 5112512025315 is 5135202152115.
It is a cyclic number.
It is not a de Polignac number, because 5112512025315 - 23 = 5112512025307 is a prime.
It is a super-2 number, since 2×51125120253152 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28175790 + ... + 28356659.
It is an arithmetic number, because the mean of its divisors is an integer number (511336010250).
Almost surely, 25112512025315 is an apocalyptic number.
5112512025315 is a deficient number, since it is larger than the sum of its proper divisors (3068864138685).
5112512025315 is a wasteful number, since it uses less digits than its factorization.
5112512025315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56538486.
The product of its (nonzero) digits is 15000, while the sum is 33.
The spelling of 5112512025315 in words is "five trillion, one hundred twelve billion, five hundred twelve million, twenty-five thousand, three hundred fifteen".
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