Base | Representation |
---|---|
bin | 100101001100101101101… |
… | …0100101111010011001001 |
3 | 200002202100221002100202112 |
4 | 1022121123110233103021 |
5 | 1132230442032324023 |
6 | 14512400412512105 |
7 | 1035240405364424 |
oct | 112313324572311 |
9 | 20082327070675 |
10 | 5112543245513 |
11 | 16a1243418670 |
12 | 6a6a1847b635 |
13 | 2b1159452472 |
14 | 13963c6369bb |
15 | 8cec7c38478 |
hex | 4a65b52f4c9 |
5112543245513 has 8 divisors (see below), whose sum is σ = 5579225412480. Its totient is φ = 4646178663280.
The previous prime is 5112543245419. The next prime is 5112543245527. The reversal of 5112543245513 is 3155423452115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5112543245513 - 212 = 5112543241417 is a prime.
It is a super-2 number, since 2×51125432455132 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5112543245543) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79362518 + ... + 79426911.
It is an arithmetic number, because the mean of its divisors is an integer number (697403176560).
Almost surely, 25112543245513 is an apocalyptic number.
It is an amenable number.
5112543245513 is a deficient number, since it is larger than the sum of its proper divisors (466682166967).
5112543245513 is a wasteful number, since it uses less digits than its factorization.
5112543245513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158792367.
The product of its digits is 360000, while the sum is 41.
Adding to 5112543245513 its reverse (3155423452115), we get a palindrome (8267966697628).
The spelling of 5112543245513 in words is "five trillion, one hundred twelve billion, five hundred forty-three million, two hundred forty-five thousand, five hundred thirteen".
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