51130113 has 4 divisors (see below), whose sum is σ = 68173488. Its totient is φ = 34086740.

The previous prime is 51130091. The next prime is 51130133. The reversal of 51130113 is 31103115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51130113 - 2⁹ = 51129601 is a prime.

It is a super-2 number, since 2×51130113² = 5228576910785538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51130092 and 51130101.

It is not an unprimeable number, because it can be changed into a prime (51130133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8521683 + ... + 8521688.

It is an arithmetic number, because the mean of its divisors is an integer number (17043372).

Almost surely, 2^51130113 is an apocalyptic number.

It is an amenable number.

51130113 is a deficient number, since it is larger than the sum of its proper divisors (17043375).

51130113 is a wasteful number, since it uses less digits than its factorization.

51130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17043374.

The product of its (nonzero) digits is 45, while the sum is 15.

The square root of 51130113 is about 7150.5323578039. The cubic root of 51130113 is about 371.1580783428.

Adding to 51130113 its reverse (31103115), we get a palindrome (82233228).

It can be divided in two parts, 5 and 1130113, that multiplied together give a palindrome (5650565).

The spelling of 51130113 in words is "fifty-one million, one hundred thirty thousand, one hundred thirteen".