Base | Representation |
---|---|
bin | 101111100111100110… |
… | …010010000000111011 |
3 | 11212222100111220120210 |
4 | 233213212102000323 |
5 | 1314203313244121 |
6 | 35253333522203 |
7 | 3460024430445 |
oct | 574746220073 |
9 | 155870456523 |
10 | 51130212411 |
11 | 1a7587433a3 |
12 | 9aab4a3363 |
13 | 4a8ac6b275 |
14 | 2690895495 |
15 | 14e3be7876 |
hex | be799203b |
51130212411 has 4 divisors (see below), whose sum is σ = 68173616552. Its totient is φ = 34086808272.
The previous prime is 51130212389. The next prime is 51130212431. The reversal of 51130212411 is 11421203115.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 51130212411 - 215 = 51130179643 is a prime.
It is a super-2 number, since 2×511302124112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51130212431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8521702066 + ... + 8521702071.
It is an arithmetic number, because the mean of its divisors is an integer number (17043404138).
Almost surely, 251130212411 is an apocalyptic number.
51130212411 is a deficient number, since it is larger than the sum of its proper divisors (17043404141).
51130212411 is a wasteful number, since it uses less digits than its factorization.
51130212411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17043404140.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 51130212411 its reverse (11421203115), we get a palindrome (62551415526).
The spelling of 51130212411 in words is "fifty-one billion, one hundred thirty million, two hundred twelve thousand, four hundred eleven".
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