Base | Representation |
---|---|
bin | 10111010000000101011111… |
… | …10100110010111001011001 |
3 | 20201001000002101010212001112 |
4 | 23220002233310302321121 |
5 | 23200204213034404340 |
6 | 300424524102430105 |
7 | 13525016011505024 |
oct | 1350025764627131 |
9 | 221030071125045 |
10 | 51130240544345 |
11 | 15323238908696 |
12 | 5899472132335 |
13 | 226b73a674b71 |
14 | c8aa070541bb |
15 | 5da035402065 |
hex | 2e80afd32e59 |
51130240544345 has 16 divisors (see below), whose sum is σ = 61877443380480. Its totient is φ = 40558225029504.
The previous prime is 51130240544323. The next prime is 51130240544431. The reversal of 51130240544345 is 54344504203115.
It is a cyclic number.
It is not a de Polignac number, because 51130240544345 - 210 = 51130240543321 is a prime.
It is a super-2 number, since 2×511302405443452 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91538759 + ... + 92095628.
It is an arithmetic number, because the mean of its divisors is an integer number (3867340211280).
Almost surely, 251130240544345 is an apocalyptic number.
It is an amenable number.
51130240544345 is a deficient number, since it is larger than the sum of its proper divisors (10747202836135).
51130240544345 is a wasteful number, since it uses less digits than its factorization.
51130240544345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183634864.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 51130240544345 in words is "fifty-one trillion, one hundred thirty billion, two hundred forty million, five hundred forty-four thousand, three hundred forty-five".
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