Base | Representation |
---|---|
bin | 100101001100111100010… |
… | …0110000110000000000011 |
3 | 200002210122011011020210211 |
4 | 1022121320212012000003 |
5 | 1132232443242143321 |
6 | 14512521234334551 |
7 | 1035255520515046 |
oct | 112317046060003 |
9 | 20083564136724 |
10 | 5113034334211 |
11 | 16a14756488a1 |
12 | 6a6b34a2a457 |
13 | 2b12071073ab |
14 | 13968794cc5d |
15 | 8d005de10e1 |
hex | 4a678986003 |
5113034334211 has 4 divisors (see below), whose sum is σ = 5130484963632. Its totient is φ = 5095583704792.
The previous prime is 5113034334173. The next prime is 5113034334227. The reversal of 5113034334211 is 1124334303115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5113034334211 - 213 = 5113034326019 is a prime.
It is a super-2 number, since 2×51130343342112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5113034334241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8725314271 + ... + 8725314856.
It is an arithmetic number, because the mean of its divisors is an integer number (1282621240908).
Almost surely, 25113034334211 is an apocalyptic number.
5113034334211 is a deficient number, since it is larger than the sum of its proper divisors (17450629421).
5113034334211 is a wasteful number, since it uses less digits than its factorization.
5113034334211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17450629420.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 5113034334211 its reverse (1124334303115), we get a palindrome (6237368637326).
The spelling of 5113034334211 in words is "five trillion, one hundred thirteen billion, thirty-four million, three hundred thirty-four thousand, two hundred eleven".
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