Base | Representation |
---|---|
bin | 10111010000000111110101… |
… | …11001010000011011111001 |
3 | 20201001010100011001002102122 |
4 | 23220003322321100123321 |
5 | 23200214303000130423 |
6 | 300425253053211025 |
7 | 13525062143653223 |
oct | 1350037271203371 |
9 | 221033304032378 |
10 | 51131500005113 |
11 | 15323824837160 |
12 | 5899763a90a75 |
13 | 226b8ab587a18 |
14 | c8aac6421413 |
15 | 5da0aac858c8 |
hex | 2e80fae506f9 |
51131500005113 has 16 divisors (see below), whose sum is σ = 57524185912320. Its totient is φ = 45051735027600.
The previous prime is 51131500005109. The next prime is 51131500005133. The reversal of 51131500005113 is 31150000513115.
It is a cyclic number.
It is not a de Polignac number, because 51131500005113 - 22 = 51131500005109 is a prime.
It is a super-2 number, since 2×511315000051132 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51131500005133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 554778245 + ... + 554870402.
It is an arithmetic number, because the mean of its divisors is an integer number (3595261619520).
Almost surely, 251131500005113 is an apocalyptic number.
It is an amenable number.
51131500005113 is a deficient number, since it is larger than the sum of its proper divisors (6392685907207).
51131500005113 is a wasteful number, since it uses less digits than its factorization.
51131500005113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1109648788.
The product of its (nonzero) digits is 1125, while the sum is 26.
Adding to 51131500005113 its reverse (31150000513115), we get a palindrome (82281500518228).
The spelling of 51131500005113 in words is "fifty-one trillion, one hundred thirty-one billion, five hundred million, five thousand, one hundred thirteen".
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