Base | Representation |
---|---|
bin | 10111010000000111110101… |
… | …11001010000011011111011 |
3 | 20201001010100011001002102201 |
4 | 23220003322321100123323 |
5 | 23200214303000130430 |
6 | 300425253053211031 |
7 | 13525062143653225 |
oct | 1350037271203373 |
9 | 221033304032381 |
10 | 51131500005115 |
11 | 15323824837162 |
12 | 5899763a90a77 |
13 | 226b8ab587a1a |
14 | c8aac6421415 |
15 | 5da0aac858ca |
hex | 2e80fae506fb |
51131500005115 has 8 divisors (see below), whose sum is σ = 61358562574848. Its totient is φ = 40904691624960.
The previous prime is 51131500005109. The next prime is 51131500005133. The reversal of 51131500005115 is 51150000513115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51131500005115 - 237 = 50994061051643 is a prime.
It is a super-2 number, since 2×511315000051152 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63104571 + ... + 63909700.
It is an arithmetic number, because the mean of its divisors is an integer number (7669820321856).
Almost surely, 251131500005115 is an apocalyptic number.
51131500005115 is a deficient number, since it is larger than the sum of its proper divisors (10227062569733).
51131500005115 is a wasteful number, since it uses less digits than its factorization.
51131500005115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127094789.
The product of its (nonzero) digits is 1875, while the sum is 28.
The spelling of 51131500005115 in words is "fifty-one trillion, one hundred thirty-one billion, five hundred million, five thousand, one hundred fifteen".
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