Base | Representation |
---|---|
bin | 101111100111101101… |
… | …000110100100100001 |
3 | 11212222110212202102222 |
4 | 233213231012210201 |
5 | 1314204243004140 |
6 | 35253440120425 |
7 | 3460045555613 |
oct | 574755064441 |
9 | 155873782388 |
10 | 51132000545 |
11 | 1a75975489a |
12 | 9ab0006115 |
13 | 4a8b446132 |
14 | 2690bdcdb3 |
15 | 14e3e4c5b5 |
hex | be7b46921 |
51132000545 has 4 divisors (see below), whose sum is σ = 61358400660. Its totient is φ = 40905600432.
The previous prime is 51132000463. The next prime is 51132000551. The reversal of 51132000545 is 54500023115.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10431762496 + 40700238049 = 102136^2 + 201743^2 .
It is a cyclic number.
It is not a de Polignac number, because 51132000545 - 216 = 51131935009 is a prime.
It is a super-2 number, since 2×511320005452 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5113200050 + ... + 5113200059.
It is an arithmetic number, because the mean of its divisors is an integer number (15339600165).
Almost surely, 251132000545 is an apocalyptic number.
It is an amenable number.
51132000545 is a deficient number, since it is larger than the sum of its proper divisors (10226400115).
51132000545 is a wasteful number, since it uses less digits than its factorization.
51132000545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10226400114.
The product of its (nonzero) digits is 3000, while the sum is 26.
The spelling of 51132000545 in words is "fifty-one billion, one hundred thirty-two million, five hundred forty-five", and thus it is an aban number.
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