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51132000545 = 510226400109
BaseRepresentation
bin101111100111101101…
…000110100100100001
311212222110212202102222
4233213231012210201
51314204243004140
635253440120425
73460045555613
oct574755064441
9155873782388
1051132000545
111a75975489a
129ab0006115
134a8b446132
142690bdcdb3
1514e3e4c5b5
hexbe7b46921

51132000545 has 4 divisors (see below), whose sum is σ = 61358400660. Its totient is φ = 40905600432.

The previous prime is 51132000463. The next prime is 51132000551. The reversal of 51132000545 is 54500023115.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10431762496 + 40700238049 = 102136^2 + 201743^2 .

It is a cyclic number.

It is not a de Polignac number, because 51132000545 - 216 = 51131935009 is a prime.

It is a super-2 number, since 2×511320005452 (a number of 22 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5113200050 + ... + 5113200059.

It is an arithmetic number, because the mean of its divisors is an integer number (15339600165).

Almost surely, 251132000545 is an apocalyptic number.

It is an amenable number.

51132000545 is a deficient number, since it is larger than the sum of its proper divisors (10226400115).

51132000545 is a wasteful number, since it uses less digits than its factorization.

51132000545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10226400114.

The product of its (nonzero) digits is 3000, while the sum is 26.

The spelling of 51132000545 in words is "fifty-one billion, one hundred thirty-two million, five hundred forty-five", and thus it is an aban number.

Divisors: 1 5 10226400109 51132000545