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5113271035 = 51171873317
BaseRepresentation
bin1001100001100011…
…00101001011111011
3111012100112002012201
410300301211023323
540432444133120
62203215051031
7240466041505
oct46061451373
914170462181
105113271035
112194343234
12ba8510a77
1363646aa82
14367148d75
151edd7d40a
hex130c652fb

5113271035 has 8 divisors (see below), whose sum is σ = 6141172176. Its totient is φ = 4087118880.

The previous prime is 5113271027. The next prime is 5113271069. The reversal of 5113271035 is 5301723115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5113271035 - 23 = 5113271027 is a prime.

It is a super-2 number, since 2×51132710352 = 52291081354739942450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5113270994 and 5113271012.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 430804 + ... + 442513.

It is an arithmetic number, because the mean of its divisors is an integer number (767646522).

Almost surely, 25113271035 is an apocalyptic number.

5113271035 is a deficient number, since it is larger than the sum of its proper divisors (1027901141).

5113271035 is a wasteful number, since it uses less digits than its factorization.

5113271035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 874493.

The product of its (nonzero) digits is 3150, while the sum is 28.

The square root of 5113271035 is about 71507.1397484195. The cubic root of 5113271035 is about 1722.7923628997.

The spelling of 5113271035 in words is "five billion, one hundred thirteen million, two hundred seventy-one thousand, thirty-five".

Divisors: 1 5 1171 5855 873317 4366585 1022654207 5113271035