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5113355550451 = 5233977136547
BaseRepresentation
bin100101001101000101110…
…1111011011111011110011
3200002211110112120201122121
41022122023233123323303
51132234123010103301
614513013151215111
71035266501020411
oct112321357337363
920084415521577
105113355550451
1116a161a9a3365
126a7004517497
132b1258823085
141396b84862b1
158d0241e13a1
hex4a68bbdbef3

5113355550451 has 4 divisors (see below), whose sum is σ = 5114332692232. Its totient is φ = 5112378408672.

The previous prime is 5113355550449. The next prime is 5113355550461. The reversal of 5113355550451 is 1540555533115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5113355550451 - 21 = 5113355550449 is a prime.

It is a super-2 number, since 2×51133555504512 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5113355550398 and 5113355550407.

It is not an unprimeable number, because it can be changed into a prime (5113355550461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 488563041 + ... + 488573506.

It is an arithmetic number, because the mean of its divisors is an integer number (1278583173058).

Almost surely, 25113355550451 is an apocalyptic number.

5113355550451 is a deficient number, since it is larger than the sum of its proper divisors (977141781).

5113355550451 is an equidigital number, since it uses as much as digits as its factorization.

5113355550451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 977141780.

The product of its (nonzero) digits is 562500, while the sum is 43.

The spelling of 5113355550451 in words is "five trillion, one hundred thirteen billion, three hundred fifty-five million, five hundred fifty thousand, four hundred fifty-one".

Divisors: 1 5233 977136547 5113355550451