511341240361 has 4 divisors (see below), whose sum is σ = 584389988992. Its totient is φ = 438292491732.

The previous prime is 511341240287. The next prime is 511341240367. The reversal of 511341240361 is 163042143115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 163042143115 = 5 ⋅32608428623.

It is a cyclic number.

It is not a de Polignac number, because 511341240361 - 2³³ = 502751305769 is a prime.

It is a super-2 number, since 2×511341240361² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (511341240367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36524374305 + ... + 36524374318.

It is an arithmetic number, because the mean of its divisors is an integer number (146097497248).

Almost surely, 2^511341240361 is an apocalyptic number.

It is an amenable number.

511341240361 is a deficient number, since it is larger than the sum of its proper divisors (73048748631).

511341240361 is an equidigital number, since it uses as much as digits as its factorization.

511341240361 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73048748630.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 511341240361 its reverse (163042143115), we get a palindrome (674383383476).

The spelling of 511341240361 in words is "five hundred eleven billion, three hundred forty-one million, two hundred forty thousand, three hundred sixty-one".