Base | Representation |
---|---|
bin | 1001100001100100… |
… | …01100011111100011 |
3 | 111012100211021001200 |
4 | 10300302030133203 |
5 | 40433014311120 |
6 | 2203222332243 |
7 | 240500312055 |
oct | 46062143743 |
9 | 14170737050 |
10 | 5113432035 |
11 | 2194443198 |
12 | ba858a083 |
13 | 6364c613a |
14 | 36718b8d5 |
15 | 1eddb0e90 |
hex | 130c8c7e3 |
5113432035 has 12 divisors (see below), whose sum is σ = 8863282272. Its totient is φ = 2727163728.
The previous prime is 5113432031. The next prime is 5113432039. The reversal of 5113432035 is 5302343115.
It is an interprime number because it is at equal distance from previous prime (5113432031) and next prime (5113432039).
It is not a de Polignac number, because 5113432035 - 22 = 5113432031 is a prime.
It is a super-2 number, since 2×51134320352 = 52294374353128482450, which contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5113432031) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 56815867 + ... + 56815956.
It is an arithmetic number, because the mean of its divisors is an integer number (738606856).
Almost surely, 25113432035 is an apocalyptic number.
5113432035 is a deficient number, since it is larger than the sum of its proper divisors (3749850237).
5113432035 is a wasteful number, since it uses less digits than its factorization.
5113432035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113631834 (or 113631831 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
The square root of 5113432035 is about 71508.2655012692. The cubic root of 5113432035 is about 1722.8104443886.
The spelling of 5113432035 in words is "five billion, one hundred thirteen million, four hundred thirty-two thousand, thirty-five".
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