Base | Representation |
---|---|
bin | 101111100111111010… |
… | …001101100101000001 |
3 | 11212222201100100112120 |
4 | 233213322031211001 |
5 | 1314211132441441 |
6 | 35254041514453 |
7 | 3460120021026 |
oct | 574772154501 |
9 | 155881310476 |
10 | 51135437121 |
11 | 1a76069183a |
12 | 9ab11a2a29 |
13 | 4a8c07a402 |
14 | 269145554d |
15 | 14e43ca966 |
hex | be7e8d941 |
51135437121 has 8 divisors (see below), whose sum is σ = 68218958304. Its totient is φ = 34071103680.
The previous prime is 51135437083. The next prime is 51135437123. The reversal of 51135437121 is 12173453115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51135437121 - 223 = 51127048513 is a prime.
It is a super-2 number, since 2×511354371212 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51135437123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4790715 + ... + 4801376.
It is an arithmetic number, because the mean of its divisors is an integer number (8527369788).
Almost surely, 251135437121 is an apocalyptic number.
It is an amenable number.
51135437121 is a deficient number, since it is larger than the sum of its proper divisors (17083521183).
51135437121 is a wasteful number, since it uses less digits than its factorization.
51135437121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9593871.
The product of its digits is 12600, while the sum is 33.
The spelling of 51135437121 in words is "fifty-one billion, one hundred thirty-five million, four hundred thirty-seven thousand, one hundred twenty-one".
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