Base | Representation |
---|---|
bin | 10111010000001111001100… |
… | …11101011110010101101011 |
3 | 20201001111112120200121011010 |
4 | 23220013212131132111223 |
5 | 23200300401222120003 |
6 | 300431145153235003 |
7 | 13525262113414032 |
oct | 1350074635362553 |
9 | 221044476617133 |
10 | 51135452145003 |
11 | 15325472701376 |
12 | 589a487562a63 |
13 | 226c08b2c0035 |
14 | c8ad7d277719 |
15 | 5da23cc05003 |
hex | 2e81e675e56b |
51135452145003 has 8 divisors (see below), whose sum is σ = 68189622681600. Its totient is φ = 34085791519208.
The previous prime is 51135452144921. The next prime is 51135452145053. The reversal of 51135452145003 is 30054125453115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51135452145003 - 218 = 51135451882859 is a prime.
It is a super-2 number, since 2×511354521450032 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51135452145053) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1127451243 + ... + 1127496596.
It is an arithmetic number, because the mean of its divisors is an integer number (8523702835200).
Almost surely, 251135452145003 is an apocalyptic number.
51135452145003 is a deficient number, since it is larger than the sum of its proper divisors (17054170536597).
51135452145003 is a wasteful number, since it uses less digits than its factorization.
51135452145003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2254955401.
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 51135452145003 its reverse (30054125453115), we get a palindrome (81189577598118).
The spelling of 51135452145003 in words is "fifty-one trillion, one hundred thirty-five billion, four hundred fifty-two million, one hundred forty-five thousand, three".
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