5114043121 has 4 divisors (see below), whose sum is σ = 5578956144. Its totient is φ = 4649130100.

The previous prime is 5114043089. The next prime is 5114043127. The reversal of 5114043121 is 1213404115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5114043121 - 2⁵ = 5114043089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5114043092 and 5114043101.

It is not an unprimeable number, because it can be changed into a prime (5114043127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232456495 + ... + 232456516.

It is an arithmetic number, because the mean of its divisors is an integer number (1394739036).

Almost surely, 2^5114043121 is an apocalyptic number.

It is an amenable number.

5114043121 is a deficient number, since it is larger than the sum of its proper divisors (464913023).

5114043121 is a wasteful number, since it uses less digits than its factorization.

5114043121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 464913022.

The product of its (nonzero) digits is 480, while the sum is 22.

The square root of 5114043121 is about 71512.5382083450. The cubic root of 5114043121 is about 1722.8790704047.

Adding to 5114043121 its reverse (1213404115), we get a palindrome (6327447236).

The spelling of 5114043121 in words is "five billion, one hundred fourteen million, forty-three thousand, one hundred twenty-one".