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5114155545241 = 50310167307247
BaseRepresentation
bin100101001101011101101…
…1011001011001010011001
3200002220112021220200012021
41022122323123023022121
51132242242304421431
614513224410014441
71035325353612631
oct112327333131231
920086467820167
105114155545241
1116a19a0530286
126a71a8417421
132b13554a3782
1413975280d6c1
158d06e566b11
hex4a6bb6cb299

5114155545241 has 4 divisors (see below), whose sum is σ = 5124322852992. Its totient is φ = 5103988237492.

The previous prime is 5114155545197. The next prime is 5114155545259. The reversal of 5114155545241 is 1425455514115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5114155545241 - 217 = 5114155414169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5114152545241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5083653121 + ... + 5083654126.

It is an arithmetic number, because the mean of its divisors is an integer number (1281080713248).

Almost surely, 25114155545241 is an apocalyptic number.

It is an amenable number.

5114155545241 is a deficient number, since it is larger than the sum of its proper divisors (10167307751).

5114155545241 is a wasteful number, since it uses less digits than its factorization.

5114155545241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10167307750.

The product of its digits is 400000, while the sum is 43.

The spelling of 5114155545241 in words is "five trillion, one hundred fourteen billion, one hundred fifty-five million, five hundred forty-five thousand, two hundred forty-one".

Divisors: 1 503 10167307247 5114155545241