Base | Representation |
---|---|
bin | 1110111000100110001… |
… | …00110000010111010001 |
3 | 1210220001211001211021002 |
4 | 13130103010300113101 |
5 | 31334342301401001 |
6 | 1030535453311345 |
7 | 51643330545206 |
oct | 7342304602721 |
9 | 1726054054232 |
10 | 511421122001 |
11 | 18798a9884a9 |
12 | 83149a95555 |
13 | 392c43a0a2a |
14 | 1aa77dd5cad |
15 | d48365946b |
hex | 77131305d1 |
511421122001 has 4 divisors (see below), whose sum is σ = 512292368112. Its totient is φ = 510549875892.
The previous prime is 511421121979. The next prime is 511421122007. The reversal of 511421122001 is 100221124115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 511421122001 - 214 = 511421105617 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (511421122007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435622175 + ... + 435623348.
It is an arithmetic number, because the mean of its divisors is an integer number (128073092028).
Almost surely, 2511421122001 is an apocalyptic number.
It is an amenable number.
511421122001 is a deficient number, since it is larger than the sum of its proper divisors (871246111).
511421122001 is an equidigital number, since it uses as much as digits as its factorization.
511421122001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 871246110.
The product of its (nonzero) digits is 160, while the sum is 20.
Adding to 511421122001 its reverse (100221124115), we get a palindrome (611642246116).
The spelling of 511421122001 in words is "five hundred eleven billion, four hundred twenty-one million, one hundred twenty-two thousand, one".
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