511500113 has 4 divisors (see below), whose sum is σ = 511672560. Its totient is φ = 511327668.

The previous prime is 511500091. The next prime is 511500137. The reversal of 511500113 is 311005115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311005115 = 5 ⋅62201023.

It is a cyclic number.

It is not a de Polignac number, because 511500113 - 2²⁶ = 444391249 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 511500091 and 511500100.

It is not an unprimeable number, because it can be changed into a prime (511500413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81695 + ... + 87732.

It is an arithmetic number, because the mean of its divisors is an integer number (127918140).

Almost surely, 2^511500113 is an apocalyptic number.

It is an amenable number.

511500113 is a deficient number, since it is larger than the sum of its proper divisors (172447).

511500113 is a wasteful number, since it uses less digits than its factorization.

511500113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172446.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 511500113 is about 22616.3682539881. The cubic root of 511500113 is about 799.7395574088.

Adding to 511500113 its reverse (311005115), we get a palindrome (822505228).

The spelling of 511500113 in words is "five hundred eleven million, five hundred thousand, one hundred thirteen".