Base | Representation |
---|---|
bin | 10111010000111101111101… |
… | …10101101010010010001011 |
3 | 20201010220100012021120001020 |
4 | 23220132332311222102023 |
5 | 23201203310120404043 |
6 | 300450500245523523 |
7 | 13530141205024521 |
oct | 1350367665522213 |
9 | 221126305246036 |
10 | 51160557200523 |
11 | 15335085872141 |
12 | 58a33131135a3 |
13 | 227155c51a184 |
14 | c8c28156a311 |
15 | 5dac0bc29e83 |
hex | 2e87bed6a48b |
51160557200523 has 4 divisors (see below), whose sum is σ = 68214076267368. Its totient is φ = 34107038133680.
The previous prime is 51160557200503. The next prime is 51160557200537. The reversal of 51160557200523 is 32500275506115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51160557200523 - 228 = 51160288765067 is a prime.
It is a super-3 number, since 3×511605572005233 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (51160557200503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8526759533418 + ... + 8526759533423.
It is an arithmetic number, because the mean of its divisors is an integer number (17053519066842).
Almost surely, 251160557200523 is an apocalyptic number.
51160557200523 is a deficient number, since it is larger than the sum of its proper divisors (17053519066845).
51160557200523 is a wasteful number, since it uses less digits than its factorization.
51160557200523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17053519066844.
The product of its (nonzero) digits is 315000, while the sum is 42.
The spelling of 51160557200523 in words is "fifty-one trillion, one hundred sixty billion, five hundred fifty-seven million, two hundred thousand, five hundred twenty-three".
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