512013115 has 4 divisors (see below), whose sum is σ = 614415744. Its totient is φ = 409610488.

The previous prime is 512013113. The next prime is 512013119. The reversal of 512013115 is 511310215.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 512013115 - 2¹ = 512013113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 512013092 and 512013101.

It is not an unprimeable number, because it can be changed into a prime (512013113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51201307 + ... + 51201316.

It is an arithmetic number, because the mean of its divisors is an integer number (153603936).

Almost surely, 2^512013115 is an apocalyptic number.

512013115 is a deficient number, since it is larger than the sum of its proper divisors (102402629).

512013115 is a wasteful number, since it uses less digits than its factorization.

512013115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102402628.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 512013115 is about 22627.7067994086. The cubic root of 512013115 is about 800.0068306708.

The spelling of 512013115 in words is "five hundred twelve million, thirteen thousand, one hundred fifteen".