Base | Representation |
---|---|
bin | 101111101011111000… |
… | …010101100000111001 |
3 | 11220011100200211222211 |
4 | 233223320111200321 |
5 | 1314330211213301 |
6 | 35304421415121 |
7 | 3461556164644 |
oct | 575370254071 |
9 | 156140624884 |
10 | 51202054201 |
11 | 1a795252181 |
12 | 9b0b56a4a1 |
13 | 4a9cb031bc |
14 | 269a236a5b |
15 | 14ea189051 |
hex | bebe15839 |
51202054201 has 4 divisors (see below), whose sum is σ = 51212256804. Its totient is φ = 51191851600.
The previous prime is 51202054159. The next prime is 51202054217. The reversal of 51202054201 is 10245020215.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 21822380176 + 29379674025 = 147724^2 + 171405^2 .
It is a cyclic number.
It is not a de Polignac number, because 51202054201 - 213 = 51202046009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51202054261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5093770 + ... + 5103811.
It is an arithmetic number, because the mean of its divisors is an integer number (12803064201).
Almost surely, 251202054201 is an apocalyptic number.
It is an amenable number.
51202054201 is a deficient number, since it is larger than the sum of its proper divisors (10202603).
51202054201 is a wasteful number, since it uses less digits than its factorization.
51202054201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10202602.
The product of its (nonzero) digits is 800, while the sum is 22.
Adding to 51202054201 its reverse (10245020215), we get a palindrome (61447074416).
The spelling of 51202054201 in words is "fifty-one billion, two hundred two million, fifty-four thousand, two hundred one".
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