Base | Representation |
---|---|
bin | 100101010000010110011… |
… | …0010101111000111101011 |
3 | 200010111112011121022221200 |
4 | 1022200230302233013223 |
5 | 1132342440220431124 |
6 | 14520131340335243 |
7 | 1035635052153543 |
oct | 112405462570753 |
9 | 20114464538850 |
10 | 5120352514539 |
11 | 16a4590564009 |
12 | 6a8437844523 |
13 | 2b1b02305202 |
14 | 139b7d852323 |
15 | 8d2d360abc9 |
hex | 4a82ccaf1eb |
5120352514539 has 6 divisors (see below), whose sum is σ = 7396064743236. Its totient is φ = 3413568343020.
The previous prime is 5120352514517. The next prime is 5120352514679. The reversal of 5120352514539 is 9354152530215.
5120352514539 is a `hidden beast` number, since 5 + 12 + 0 + 3 + 52 + 51 + 4 + 539 = 666.
It is not a de Polignac number, because 5120352514539 - 215 = 5120352481771 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5120352514494 and 5120352514503.
It is not an unprimeable number, because it can be changed into a prime (5120352514339) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 284464028577 + ... + 284464028594.
It is an arithmetic number, because the mean of its divisors is an integer number (1232677457206).
Almost surely, 25120352514539 is an apocalyptic number.
5120352514539 is a deficient number, since it is larger than the sum of its proper divisors (2275712228697).
5120352514539 is a wasteful number, since it uses less digits than its factorization.
5120352514539 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 568928057177 (or 568928057174 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 45.
The spelling of 5120352514539 in words is "five trillion, one hundred twenty billion, three hundred fifty-two million, five hundred fourteen thousand, five hundred thirty-nine".
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