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5121421513345 = 51024284302669
BaseRepresentation
bin100101010000110110010…
…0000101001001010000001
3200010121021200010002122001
41022201230200221022001
51132402132401411340
614520425404544001
71036003412411254
oct112415440511201
920117250102561
105121421513345
1116a4a89a246a5
126a8695852001
132b1c42920297
14139c4180109b
158d3473bb29a
hex4a86c829281

5121421513345 has 4 divisors (see below), whose sum is σ = 6145705816020. Its totient is φ = 4097137210672.

The previous prime is 5121421513303. The next prime is 5121421513349. The reversal of 5121421513345 is 5433151241215.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2799735444081 + 2321686069264 = 1673241^2 + 1523708^2 .

It is a cyclic number.

It is not a de Polignac number, because 5121421513345 - 215 = 5121421480577 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5121421513349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512142151330 + ... + 512142151339.

It is an arithmetic number, because the mean of its divisors is an integer number (1536426454005).

Almost surely, 25121421513345 is an apocalyptic number.

It is an amenable number.

5121421513345 is a deficient number, since it is larger than the sum of its proper divisors (1024284302675).

5121421513345 is a wasteful number, since it uses less digits than its factorization.

5121421513345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1024284302674.

The product of its digits is 72000, while the sum is 37.

The spelling of 5121421513345 in words is "five trillion, one hundred twenty-one billion, four hundred twenty-one million, five hundred thirteen thousand, three hundred forty-five".

Divisors: 1 5 1024284302669 5121421513345