Base | Representation |
---|---|
bin | 101111101101000001… |
… | …010000110100101011 |
3 | 11220012200200002222220 |
4 | 233231001100310223 |
5 | 1314400104441444 |
6 | 35310343245123 |
7 | 3462210526341 |
oct | 575501206453 |
9 | 156180602886 |
10 | 51221171499 |
11 | 1a7a501a2a3 |
12 | 9b15a497a3 |
13 | 4aa3a67904 |
14 | 269c9b1991 |
15 | 14ebbb3619 |
hex | bed050d2b |
51221171499 has 16 divisors (see below), whose sum is σ = 69329971200. Its totient is φ = 33630141600.
The previous prime is 51221171471. The next prime is 51221171579. The reversal of 51221171499 is 99417112215.
51221171499 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 51221171499 - 25 = 51221171467 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51221171499.
It is not an unprimeable number, because it can be changed into a prime (51221171999) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 938049 + ... + 991149.
It is an arithmetic number, because the mean of its divisors is an integer number (4333123200).
Almost surely, 251221171499 is an apocalyptic number.
51221171499 is a deficient number, since it is larger than the sum of its proper divisors (18108799701).
51221171499 is a wasteful number, since it uses less digits than its factorization.
51221171499 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57970.
The product of its digits is 45360, while the sum is 42.
The spelling of 51221171499 in words is "fifty-one billion, two hundred twenty-one million, one hundred seventy-one thousand, four hundred ninety-nine".
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