Base | Representation |
---|---|
bin | 10111010011001000110111… |
… | …11111001110100010011001 |
3 | 20201102000211121111112001122 |
4 | 23221210123333032202121 |
5 | 23203414023403332213 |
6 | 300545032410455025 |
7 | 13535421252034526 |
oct | 1351443377164231 |
9 | 221360747445048 |
10 | 51235134433433 |
11 | 15363775766025 |
12 | 58b5866a34475 |
13 | 22785b6040062 |
14 | c91b1803414d |
15 | 5dcb240d2d08 |
hex | 2e991bfce899 |
51235134433433 has 8 divisors (see below), whose sum is σ = 51335601897888. Its totient is φ = 51134676525504.
The previous prime is 51235134433421. The next prime is 51235134433463. The reversal of 51235134433433 is 33433443153215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51235134433433 - 232 = 51230839466137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51235134433463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8391566 + ... + 13148712.
It is an arithmetic number, because the mean of its divisors is an integer number (6416950237236).
Almost surely, 251235134433433 is an apocalyptic number.
It is an amenable number.
51235134433433 is a deficient number, since it is larger than the sum of its proper divisors (100467464455).
51235134433433 is a wasteful number, since it uses less digits than its factorization.
51235134433433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4778263.
The product of its digits is 2332800, while the sum is 44.
Adding to 51235134433433 its reverse (33433443153215), we get a palindrome (84668577586648).
The spelling of 51235134433433 in words is "fifty-one trillion, two hundred thirty-five billion, one hundred thirty-four million, four hundred thirty-three thousand, four hundred thirty-three".
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