Base | Representation |
---|---|
bin | 10111010011010010111100… |
… | …10000011100111110000001 |
3 | 20201102112210102022100122212 |
4 | 23221221132100130332001 |
5 | 23204011112022300140 |
6 | 300551325112511505 |
7 | 13536002243640116 |
oct | 1351513620347601 |
9 | 221375712270585 |
10 | 51240541212545 |
11 | 15365a9a749213 |
12 | 58b69156ab595 |
13 | 2278c68244a39 |
14 | c920ac14290d |
15 | 5dcd3dadb765 |
hex | 2e9a5e41cf81 |
51240541212545 has 16 divisors (see below), whose sum is σ = 62921189802240. Its totient is φ = 40037484004224.
The previous prime is 51240541212541. The next prime is 51240541212571. The reversal of 51240541212545 is 54521214504215.
51240541212545 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 51240541212545 - 22 = 51240541212541 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (51240541212541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 414821 + ... + 10131789.
It is an arithmetic number, because the mean of its divisors is an integer number (3932574362640).
Almost surely, 251240541212545 is an apocalyptic number.
It is an amenable number.
51240541212545 is a deficient number, since it is larger than the sum of its proper divisors (11680648589695).
51240541212545 is a wasteful number, since it uses less digits than its factorization.
51240541212545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9741544.
The product of its (nonzero) digits is 320000, while the sum is 41.
The spelling of 51240541212545 in words is "fifty-one trillion, two hundred forty billion, five hundred forty-one million, two hundred twelve thousand, five hundred forty-five".
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