Base | Representation |
---|---|
bin | 100101010010001111001… |
… | …0010110110010011000011 |
3 | 200010212222112122101121000 |
4 | 1022210132102312103003 |
5 | 1132424234441212403 |
6 | 14522041355103043 |
7 | 1036140341240103 |
oct | 112443622662303 |
9 | 20125875571530 |
10 | 5124404241603 |
11 | 16a627a668579 |
12 | 6a9188741a83 |
13 | 2b22c986814a |
14 | 13a0459cd203 |
15 | 8d46e19c7a3 |
hex | 4a91e4b64c3 |
5124404241603 has 16 divisors (see below), whose sum is σ = 7634121782400. Its totient is φ = 3397184186760.
The previous prime is 5124404241563. The next prime is 5124404241653. The reversal of 5124404241603 is 3061424044215.
5124404241603 is a `hidden beast` number, since 5 + 1 + 2 + 4 + 4 + 0 + 4 + 2 + 41 + 603 = 666.
It is not a de Polignac number, because 5124404241603 - 28 = 5124404241347 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5124404241653) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 530142513 + ... + 530152178.
It is an arithmetic number, because the mean of its divisors is an integer number (477132611400).
Almost surely, 25124404241603 is an apocalyptic number.
5124404241603 is a deficient number, since it is larger than the sum of its proper divisors (2509717540797).
5124404241603 is a wasteful number, since it uses less digits than its factorization.
5124404241603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1060294879 (or 1060294873 counting only the distinct ones).
The product of its (nonzero) digits is 92160, while the sum is 36.
Adding to 5124404241603 its reverse (3061424044215), we get a palindrome (8185828285818).
The spelling of 5124404241603 in words is "five trillion, one hundred twenty-four billion, four hundred four million, two hundred forty-one thousand, six hundred three".
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